-h^2+60h-36=0

Solution for -h^2+60h-36=0 equation:

-h^2+60h-36=0

We add all the numbers together, and all the variables

-1h^2+60h-36=0

a = -1; b = 60; c = -36;
Δ = b2-4ac
Δ = 602-4·(-1)·(-36)
Δ = 3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3456}=\sqrt{576*6}=\sqrt{576}*\sqrt{6}=24\sqrt{6}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-24\sqrt{6}}{2*-1}=\frac{-60-24\sqrt{6}}{-2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+24\sqrt{6}}{2*-1}=\frac{-60+24\sqrt{6}}{-2}
$